A projectile of mass `50 kg` is shot vertically upwards with n initial velocity of `100m//s`. After `5s`, it explodes into two fragments, one of (1st fragment) which having a mass of `20 kg` travels vertically up with a velovity of `150m//s (g = 10 m//s^(2))`. Bases on the above paragraph answer the following questions.
What is the linear momentum of `2nd` fragement `3s` after the explosion is

Options

A. `140//3 kg-m//s`
B. `40//3 kg-m//s`
C. `80//3 kg-m/s`
D. `100//3 kg-m//s`

Answer

A

Explanation

Velocity of projectile after `5s` is `= 50 m//s`
Total momentum before explosion `=` Total momentum after explosion.
`m xx 50 = m_(1)v_(1)+m_(2)v_(2)`
`50 xx 50 = 20 xx 150 - 30 xx v_(2)`
`v_(2) = (50)/(3)m//s` (velocity of 2nd fragment just after explosion)
velocity of `2^(nd)` fragment `3s` after the explosion is `= (50)/(3) + 10 xx 3 = (140)/(3)`,
momentum of `2^(nd)` fragement `3s` after the explosion is `(140)/(3) xx 30`
Velocity of `1^(st)` one `3s` after the explosion is `= 150-10 xx 3 = 120 m//s`
Sum of momentum of two fragment `3s` after the explosion `= 20 xx 120 - (30 xx 140)/(3)=2400-1400 = 1000 kg-m//s`