For a circuit shown in fig find the value of resistance `R_(2)` and current `I_(2)` flowing thorugh `R_(2)`

Explanation

If equivalent resistance of parallel
combination of `R_(1)` and `R_(2)` is `R`, then
`R=(R_(1)R_(2))/(R_(1)+R_(2))=(10R_(2))/(10+R_(2))`
According to Ohm's law `R=(V)/(I)`
`R=(50)/(10)=5Omegaimplies(10R_(2))/(10+R_(2))=5impliesR_(2)=10Omega`
The current is equally divided into `R_(1)` and `R_(2)` Hence `I_(2)=5A`