Find potential difference between points A and B of the network shown in fig. and distribution of given main current through different resistors.

Explanation

Between point A and B resistors of `4Omega,6Omega` and `8Omega` resistances are in series and these are in parallel to `9Omega` resistor. ,brgt Equivalent resistance of series combination is
`R_(1)=(4+6+8)ohm=18`
If equivalent resistance between A and B is
`R=(9xx18)/((9+18))ohm=6Omega`
Potential difference between A and B is
`V=IR=2.7xx6V=16.2V`
Current through `9Omega` resistor `=(16.2)/(9)=1.8A`
Current through `4Omega,6Omega` and `8Omega` resistors `=2.7-1.8=0.9A`