A fuse wire with radius of `0.2mm` blows off with a current of 5 Amp. The fuse wire of same material,but of radius 0.3 mm will blow off with a current of
(1) `5xx(3)/(2)Amp`
(2). `(5sqrt(3))/(2)Amp`
(3). `5sqrt((27)/(8))Amp`
(4). `5 Amp`

Explanation

`i^(2)propr^(3),(i_(1))/(i_(2))=((r_(1))/(r_(2)))^((3)/(2))=((0.2)/(0.3))^((3)/(2))`
`i_(2)=5sqrt((27)/(8))Amp`