In the given circuit as shown below calculate the magnitude and direction of the current

Explanation

Effective resistance of the circuit is
`R_(eff)=2+2+1=5Omega`
`therefore` total current in the circuit is `i=(V_(1)-V_(2))/(R_(eff))`
`i=(10-15)/(5)=1A`
Since the cell of larger emf decides the direction of low of current the direction of current in the circuit is from A to B through e