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A uniform wire resistance 20 Omega havi...

A uniform wire resistance `20 Omega` having resistance `1 Omega per meter, ` is bent in the forms of a circuit if the equal - valent resistance between A and B is `1.8 Omega ` then length of the shorter section is

A

2m

B

5m

C

1.8 m

D

18m

Text Solution

Verified by Experts

The correct Answer is:
A
Let the resistance of shorter part MN be x.
Then resistance of longer part is `(20-x)Omega`
`R_(eq)=((20-x)x)/(20-x+x)=1.8Omega`
solving we get `x=2Omega`
So length of shorter part `=2m`
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