Two resistance of 400 Omega and 800 Omeg...

Two resistance of `400 Omega` and `800 Omega` are connected in series with 6 volt battery of negligible internal resistance. A voltmeter of resistance `10,000 Omega` is used to measure the potential difference across `400 Omega`. The error in measurement of potential difference in volts approximatley is

0.05V

0.5V

0.75V

Text Solution

Verified by Experts

The correct Answer is:

error`=V_(1)-V_(1)^(1)`

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