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Twenty four cells each of emf 1.5 V and ...

Twenty four cells each of emf 1.5 V and internal resistance 0.5 ohms are to be connected to a 3 ohm resistance. For maximum current through this resistance the nuber of rows and number of columns that you connect these cells is.

A

12 cells in series 2 ros in parallel

B

8 cells in series 3 rows in parallel

C

4 cells in series 6 rows in parallel

D

6 cells in series 4 rows in parallel

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To solve the problem of connecting 24 cells each with an emf of 1.5 V and an internal resistance of 0.5 ohms to a 3-ohm external resistance for maximum current, we will follow these steps: ### Step 1: Understand the Configuration We need to determine how to arrange the 24 cells in terms of rows (series) and columns (parallel) to maximize the current through the external resistance. ### Step 2: Define Variables Let: - N = number of cells in series (rows) - M = number of parallel paths (columns) ### Step 3: Calculate Effective Resistance The effective resistance (R_eff) when N cells are connected in series and M paths are in parallel is given by: \[ R_{\text{eff}} = \frac{N \cdot r}{M} \] where \( r \) is the internal resistance of each cell (0.5 ohms). ### Step 4: Set Up the Equation for Maximum Current For maximum current, the external resistance (R) should equal the effective resistance: \[ R = R_{\text{eff}} \] Substituting the values: \[ 3 = \frac{N \cdot 0.5}{M} \] ### Step 5: Rearranging the Equation From the equation above, we can express N in terms of M: \[ N = 6M \] ### Step 6: Total Number of Cells Since there are a total of 24 cells, we have the equation: \[ N \cdot M = 24 \] ### Step 7: Substitute N in the Total Cells Equation Substituting \( N = 6M \) into the total cells equation: \[ 6M \cdot M = 24 \] This simplifies to: \[ 6M^2 = 24 \] \[ M^2 = 4 \] \[ M = 2 \] ### Step 8: Calculate N Now, substituting M back to find N: \[ N = 6M = 6 \cdot 2 = 12 \] ### Conclusion Thus, the number of cells connected in series (N) is 12, and the number of parallel paths (M) is 2. Therefore, the cells should be connected as follows: - **Number of rows (series)**: 12 - **Number of columns (parallel)**: 2 ### Final Answer The number of rows and columns to connect the cells for maximum current through the 3-ohm resistance is: - **Rows (N)**: 12 - **Columns (M)**: 2 ---

To solve the problem of connecting 24 cells each with an emf of 1.5 V and an internal resistance of 0.5 ohms to a 3-ohm external resistance for maximum current, we will follow these steps: ### Step 1: Understand the Configuration We need to determine how to arrange the 24 cells in terms of rows (series) and columns (parallel) to maximize the current through the external resistance. ### Step 2: Define Variables Let: - N = number of cells in series (rows) ...
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