The potential difference between points A and B is

Options

A. `1.50 V`
B. `2.50 V`
C. `1.00 V`
D. `0.50 V`

Answer

D

Explanation

For the first loop `12=5i+i_(1)`
for the second loop `0=7(i-i_(1))-i_(1)`
or `8i_(1)=7i` or `i_(1)=((7)/(8))i`
Therefore, we obtain `12=5i+(7)/(8)i=(47i)/(8)`
or, `i=(12xx8)/(47)A=2.04A`
`i_(1)=(7)/(8)xx2.04A=1.79A`
Thus, the p.d. across A and B is
`V_(A)-V_(B)=(i-i_(1))xx2=0.25xx2=0.50V`