Masses fo three are in the ratio `1:3:5` their lengths are in the ratio `5:3:1` when they are connected in series to an external source, te amounts of heats produced in them are in the ratio

Options

A. `125:15:1`
B. `1:15:125`
C. `5:3:1`
D. `1:3:5`

Answer

A

Explanation

`m_(1):m_(2):m_(3)=1:3:5`
`l_(1):l_(2):l_(3)=5:3:1`
`Q=i^(2)Rt`
`R=(rhodl^(2))/(m)`
`QalphaR=(rhodl^(2))/(m)`
`(Q_(1))/(Q_(2))=(l_(1)^(2))/(l_(2)^(2))xx(m_(2))/(m_(1))impliesQ_(1):Q_(2):Q_(3)=125:15:1`