Home
Class 12
PHYSICS
In the following circuit, 5Omega resisto...


In the following circuit, `5Omega` resistor develops 45 J/s due to current flowing through it. The power developed across `12Omega` resistor is

A

16 W

B

192 W

C

36 W

D

64 W

Text Solution

Verified by Experts

The correct Answer is:
B

`P=i^(2)R=192W`
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    NARAYNA|Exercise NCERT Based Questions|13 Videos
  • CURRENT ELECTRICITY

    NARAYNA|Exercise Level 5|42 Videos
  • CURRENT ELECTRICITY

    NARAYNA|Exercise Level 2 H.W|45 Videos
  • COMMUNICATION SYSTEM

    NARAYNA|Exercise Level-II(H.W)|25 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NARAYNA|Exercise ASSERTION AND REASON|15 Videos

Similar Questions

Explore conceptually related problems

In the following circuit, 18Omega resistor develops 2J/sec due to current flowing through it. The power developed across 10Omega resistance is

In the circuit shown in figure, the 5 Omega resistance develops 20.00 cal//s due to the current flowing through it. The heat developed in 2 Omega resistance (in cal //s ) is

Current flowing through 4 Omega resistor is :

In the circuit shown in Fig.6.2, the heat produced in 5Omega resistor, due to the current flowing through it is 10 calorie per second. Find the heat produced in 4Omega resistor.

In the circuit shown in Fig.6.2, the heat produced in 5Omega resistor, due to the current flowing through it is 10 calorie per second. Find the heat produced in 4Omega resistor.

In the circuit shown in the following figure, the heat product in the 5 Omega resistance due to the current flowing it is 10 cal/s. The heat generated in 4Omega resistance and 6 Omega resistor is

Current through the 5Omega resistor is

Find the current through 12 Omega resistor in

In the circuit shown below, the power developed in the 6 Omega resistor is 6 watt. The power in watts developed in the 4 Omega resistor is

NARAYNA-CURRENT ELECTRICITY-Level 3
  1. Masses fo three are in the ratio 1:3:5 their lengths are in the ratio ...

    Text Solution

    |

  2. A heater coil rated at 1000 W s connected to a 110 V mains. How much t...

    Text Solution

    |

  3. In the following circuit, 5Omega resistor develops 45 J/s due to curre...

    Text Solution

    |

  4. Two wires 'A' and 'B' of the same material have their lengths in the r...

    Text Solution

    |

  5. An electric motor operating on 50 volt D.C. supply draws a current of ...

    Text Solution

    |

  6. Find the resistance of 240 V - 200 watt electric bulb when glowing. If...

    Text Solution

    |

  7. A wire of length L and 3 identical cells of negligible internal resist...

    Text Solution

    |

  8. Three bulbs with their power and working voltage are connected as show...

    Text Solution

    |

  9. A cell of emf 12 V and internal resistance 6Omega is connected in para...

    Text Solution

    |

  10. A cell develops the same power across two resistances R(1) and R(2) se...

    Text Solution

    |

  11. A metallic conductor at 10^(@)C connected in the left gap of meter bri...

    Text Solution

    |

  12. When a conducting wire is connected in the right gap and known resista...

    Text Solution

    |

  13. n identical resistors are taken (n)/(2) resistors are connected in ser...

    Text Solution

    |

  14. In a metere bridge, the balance length from left end (standard resista...

    Text Solution

    |

  15. In an experiment with a potentiometer to measure the internal resistan...

    Text Solution

    |

  16. A potentiometer wire of lengthh 100 cm has resistance 5Omega. It is co...

    Text Solution

    |

  17. 1 ohm resistance is in series with a Ammeter which is balanced by 75 c...

    Text Solution

    |

  18. A potentiometer wire of lengthh 100 cm has resistance 5Omega. It is co...

    Text Solution

    |

  19. In an experiment for calibration of voltmeter, standard cell of emf 1....

    Text Solution

    |

  20. In the circuit shown in fig. the potential difference between the poin...

    Text Solution

    |