`n` identical resistors are taken `(n)/(2)` resistors are connected in series and the remaining are connected in paralle. The series connected group is kept in the left gap of a meter bridge and the parallel connected group in the right gap. The distance of te balance point from the left end of the wire is

Options

A. `(100n^(2))/(n^(2)+4)`
B. `(100n^(2))/(n^(2)+1)`
C. `(400)/(n^(2)+4)`
D. `(400)/(n^(2)+1)`

Answer

A

Explanation

`(X)/(100-X)=((nr)/(2))/((2r)/(n))`