The magnetic moment of a magnet is `3.6xx10^(-3)A.m^(2)`. Its pole strength is `120`mili amp.M`. Its magnetic length is

Options

A. `3cm`
B. `0.3cm`
C. `33.33cm`
D. `3x10^(-2)cm`

Explanation

To find the magnetic length \( l \) of a magnet given its magnetic moment \( m \) and pole strength \( p \), we can use the formula:

\[ m = p \cdot l \]

Where:
- \( m \) is the magnetic moment in \( A \cdot m^2 \)
- \( p \) is the pole strength in \( A \cdot m \)
- \( l \) is the magnetic length in meters

### Step-by-Step Solution:

1. **Identify the given values**:
- Magnetic moment \( m = 3.6 \times 10^{-3} \, A \cdot m^2 \)
- Pole strength \( p = 120 \, mA \cdot m = 120 \times 10^{-3} \, A \cdot m \)

2. **Substitute the values into the formula**:
\[ 3.6 \times 10^{-3} = (120 \times 10^{-3}) \cdot l \]

3. **Rearranging the formula to solve for \( l \)**:
\[ l = \frac{m}{p} \]

4. **Plug in the values**:
\[ l = \frac{3.6 \times 10^{-3}}{120 \times 10^{-3}} \]

5. **Simplify the expression**:
\[ l = \frac{3.6}{120} = 0.03 \, m \]

6. **Convert meters to centimeters**:
\[ l = 0.03 \, m = 3 \, cm \]

### Final Answer:
The magnetic length \( l \) is \( 3 \, cm \).

---