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The work done in turning a magnet of mag...

The work done in turning a magnet of magnetic moment 'M' by an angle of `90^(@)` from the meridian is 'n' times the corresponding work done to turn it through an angle of `60^(@)`, where 'n' is given by

A

`(1)/(2)`

B

`2`

C

`(1)/(4)`

D

`1`

Text Solution

Verified by Experts

The correct Answer is:
B
`W=MB sintheta_(1)-cotheta_(2)`
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