A bar magnet of length 'I' breadth 'b' m...

A bar magnet of length `'I'` breadth `'b'` mass `'m'` suspended horizontally in the earths magnetic field, oscillates with period `T`. If `'I'm,b` are doubled with pole strength remaining the same, the now will be

`8T`

`4T`

`T//2`

`2T`

Text Solution

Verified by Experts

The correct Answer is:

`T=2pisqrt((I)/(MB)),I=(m)/(12)(l^(2)+b^(2))`

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NARAYNA-MAGNETISM-LEVEL-I(C.W)

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