Two short magnets of equal dipole moments `M` are fastened perpendicularly at their centres (figure). The magnitude of the magnetic field at a distance `d` from the centre on the bisector of the right angle is

Options

A. `(mu_(0))/(4pi)(m)/(d^(3))`
B. `(mu_(0))/(4pi)(2sqrt2M)/(d^(3))`
C. `(mu_(0))/(4pi)(2M)/(d^(3))`
D. `(mu_(0))/(2pi)(M)/(d^(3))`

Answer

B

Explanation

`VB=(mu_(0))/(4pi)(2M cos 45)/(d^(3))xx2`