A short bar magnet is placed with its south pole facing geographic south and the distance between the null point is found to be `16 cm`. When the magnet is turned pole to pole at the same place then the distance between the null points will be

Options

A. will be same , along the axial line
B. will be same , along the equatorial line
C. will be `16xx2^(1//3)`, on the axial line
D. will be `16xx2^(1//3)` , on the equatorial line

Answer

C

Explanation

`B_(H)=B_(e)=(mu_(0)2M)/(4pid_(1)^(3)) B_(H)=B_(a)=(mu_(0)M)/(4pid_(2)^(3))`