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A bar magnet is placed with its North po...

A bar magnet is placed with its North pole pointing North. Neutral point is at `12 cm`. Another magnet is now placed on the first magnet, then the neutral point is found to be at `8 cm`. The ratio of their magnetic moments is

A

`3:2`

B

`27:19`

C

`9:4`

D

`9:5`

Text Solution

Verified by Experts

The correct Answer is:
B
`(mu_(0))/(4pi)(M_(1))/(12^(3))=B_(H)` and `(mu_(0))/(4pi)((M_(1)-M_(2)))/(8^(3))=B_(H)`
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