The correct value of dip angle at a place is `45^(@)`. If the dip circle is rotated by `45^(@)` out of the meridian, then the tangent of the angle of apparent dip at the place is

Options

A. `1`
B. `1//2`
C. `1sqrt2`
D. `sqrt2`

Answer

D

Explanation

`tan delta=(B_(V))/(B_(H))` and
`tan delta^(1)=(B_(V)^(1))/(B_(H)^(1))=(B_(V))/(B_(H) cos 45^(@))`
`tan delta^(1)=(tan delat)/(cos 45)`