A rod of cross sectional area 10cm^(2) i...

A rod of cross sectional area `10cm^(2)` is placed with its length parallel to a magnetic field of intensity `1000 A//M` the flux through the rod is `10^(4)`webers. The the permeability of material of rod is

`10^(4)wb//Am`

`10^(3)wb//Am`

`10^(2)wb//Am`

`10wb//Am`

Text Solution

Verified by Experts

The correct Answer is:

`mu=(phi)/(AH)`

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