Arrheniusd eqwuation shows similarity with

Options

A. Nernst equation
B. Maxwell equation
C. Clausius - Clapeyron equation
D. van't Hoff equation

Answer

D

Explanation

if the temperature are `T_(1)` and `T_(2)` and the specific rate constant are `K_(1)` and `k_(2)` , then using Arrhenius equation we can derive a relationship between the activation energy `E_(a)` and the specific rate constant that are neasured at any two temperatures:
`In(k_(2))/(k_(1))=(E_(a))/(R)[(T_(2)-T_(1))/(T_(1)T_(2))]`
or solving for `E_(a)` :
`E_(a)=R[(T_(1)T_(2))/(T_(2)-T_(1))][In(k_(2))/(k_(1))]`
These equations resemble van't Hoff equation, which gives the temperature dependence of the equlibrium constant.
`In(k_(2))/(k_(1))=(Delta^(@))/(R)[(T_(2)-T_(1))/(T_(1)T_(2))]`