Consider the following sequence of reactions
`CH_(2)=CHCH=CH_(2)underset(C CI_(4))overset(Br_(2)(1mol e))rarrA underset(2H_(2),Ni)overset(1KCN(excess))rarrB` .

Options

A. `CH_(2)=CH-overset(NH_(2))overset(||)CH-CH_(2)NH_(2)`
B. `NC CH_(2)CH=CHCH_(2)CH`
C. `H_(2)N(CH_(2))_(6)NH_(2)`
D. `CH_(2)=CH-underset(CH_(2)NH_(2))underset(|)CH_(2)-CH_(2)NH_(2)`

Answer

C

Explanation

First step involves `1,4-`addition of `Br_(2)` to yield to dibromide which undergoes nuclephilic substitution to yield dicyanide which yields diamine on reduction
.