`H_(2)C=CHCH_(2)Br+N_(3)^(_)rarrAunderset(1LiAIH_(4))overset(2.H_(2)O)rarrB`
Identify compound `B` .

Options

A. `CH_(3)CH_(2)CH_(2)NH_(2)`
B. `CH_(3)CH(NH_(2))CH_(3)`
C. `CH_(2)=CHCH_(2)NH_(2)`
D. `H_(2)NCH_(2)CH_(2)CH_(2)NH_(2)`

Answer

C

Explanation

A is `H_(2)C=CHCH_(2)N_(3)` formed bt `S_(N)2` displacement of `Brbar` by `N_(3)bar` B is `H_(2)C=CHCH_(2)NH_(2)` because `LiAIH_(4)` does not reduce the double bond it reduces only the azide group Note that alky1 azides are explosives They should not be isolated but be reacted only in situ .