A uniform chain of length `2m` is kept on a table such that a length of `60 cm` hangas freely from the adge of the table . The table . The total mass of the chain ia `4 kg` What is the work done in pulling the entire the chain the on the table ?

Explanation

`M = 4 kg, L = 2m, l = 0.6m, g = 10 m//s^(2)`
Work done `W = mg l/(2) = ((M)/(L)) l g"(l)/(2)`
`W = ((4)/(2)) xx 0.6 xx 10 xx (0.6)/(2) = 3.6 J`.