Find the work done in lifting a body of mass `20 kg` and specific gravity `3.2` to a height of `8 m` in water ? `(g = 10 m//s^(2))`.

Explanation

To find the work done in lifting a body of mass \(20 \, \text{kg}\) and specific gravity \(3.2\) to a height of \(8 \, \text{m}\) in water, we can follow these steps:

### Step 1: Understand Specific Gravity
Specific gravity is the ratio of the density of a substance to the density of water. The specific gravity of the body is given as \(3.2\), which means:
\[ \text{Density of the body} = 3.2 \times \text{Density of water} \]
Since the density of water is approximately \(1000 \, \text{kg/m}^3\), we can calculate the density of the body:
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