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A particle is projected at 60(@) to the...

A particle is projected at ` 60(@)` to the horizontal with a kinetic energy `K` . The kinetic energy at the highest point is

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Initial kinetic energy is `K = (1)/(2) m u^(2)`
The velocity at highest point `v_(x) = u cos theta`.
kinetic energy of a particle at highest point
`K_(H) = (1)/(2) mv_(x)^(2) = (1)/(2) m u^(2) cos^(2) theta = K cos^(2) 60^@ = (K)/(4)`.
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