The figure shown a particle sliding on a frictionless track, which teminates in a straight horizontal section. If the particle starts slipping from the point `A`, how far away from the track will the particle hit the ground?

Explanation

Applying the law of conservation of mechanical energy for the points `A` and `B`,
`mgH = (1)/(2) mv^(2) + mgh`
`g -(v^(2))/(2) = (g)/(2)` or `v^(2) = g rArr v = sqrt(g) = 3.1 ms^(-1)`
After point `B` the particle exhibits projectile motion
with `theta = 0^(0)` and `y = - 0.5 m`
Horizontal distance travelled by the body
`R = u sqrt((2h)/(g)) = 3.1 xx sqrt((2 xx 0.5)/(9.8)) = 1m`.