Two bodies of masses `m_(1)` and `m_(2)` are moving with velocities `1 ms^(-1)` and `3ms^(-1)` respectively in opposite directions. If the bodies undergo one dimensional elastic collision, the body of mass `m_(1)` comes to rest. Find the ration of `m_(1)` and `m_(2)`.

Explanation

`u_(1) 1m//s, u_(2) = -3m//s,v_(1) = 0`
`v_(1) =((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1) +((2m_(2))/(m_(1)+m_(2)))u_(2)`
`0 =((m_(1) -m_(2))/(m_(1)+m_(2)))1+ ((2m_(2))/(m_(1)+m_(2))) (-3)`
`m_(1)-m_(2)=6m_(2) ,m_(1) =7m_(2), (m_(1))/(m_(2)) = (7)/(1)`.