A block of mass `0.50kg` is moving with a speed of `2.00m//s` on a smooth surface. It strikes another mass of `1 kg` at rest and they move as a single body. The energy loss during the collision is

Explanation

From `LCLM, m_(1)u_(1) + m_(2)u_(2) = (m_(1) + m_(2))v`
`0.50 xx 2+1 xx 0=(0.5 +1) v rArr v = (2)/(3) ms^(-1)`
`:.` Energy loss `DeltaKE = (1)/(2) m_(1)u_(1)^(2) -(1)/(2) (m_(1) + m_(2)) v^(2)`
`Delta KE = (1)/(2)(0.5)(2)^(2) -(1)/(2) (1.5) ((2)/(3))^(2) = 0.67 J`.