A body of mass 10 kg moving with a veloc...

A body of mass `10 kg` moving with a velocity of `5 ms^(-1)` hits a body of `1 gm` at rest. The velocity of the second body after collision. Assuming it to be perfectly elastic is

`10 ms^(-1)`

`5 ms^(-1)`

`15 ms^(-1)`

`0.10 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

`v_(2) = ((2m_(1))/(m_(1)+m_(2)))u_(1)`

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