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A block of mass m = 1 kg is released fro...

A block of mass `m = 1 kg` is released from point `A` along a smooth track as shown. Part `AB` is circular with radius `r_(1) = 4 m` and circular at `C` with radius `r_(2)`. Height of point `A` is `h_(1) = 2m` and of `c` is `h_(2) = 1m (g = 10 m//s^(2))`.
.
The force exerted by block on the track at `B` is

A

10 N

B

20 N

C

30 N

D

40 N

Text Solution

Verified by Experts

The correct Answer is:
B

`v_(2) = sqrt(2gh_(1)) , N = mg + (mv_(2)^(2))/(r_(1))`.
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