Assuming pure 2s and 2p orbitals of carbon are used in forming `CH_(4)` molecule, which of the following statement is false ?

Options

A. Three C-H bonds will be at right angle
B. One C-H bond will be weaker than other three C-H bonds
C. The shape of molecule will be tetrahedral
D. The angle of C-H bond formed by s-s overlapping will be uncertain with respect to other three bonds.

Answer

C

Explanation

In the unhybridized state of carbon, 2p orbitals are `90^(@)` to one another and each one will overlap with 1s orbital of three hydrogen atoms, thus three C-H bonds are formed which are `90^(@)` to one another. For the fourth hydrogen atom, its 1s orbital may overlap with non-directional 2s orbital of the carbon and this `sigma`-bond will be stronger than `sigma`C-H bonds formed by 2p-1s overlap. In such situation `CH_(4)` molecule can never has tetrahedral geometry.