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A rod with linear charge density lambda ...

A rod with linear charge density `lambda` is bent in the shap of circular ring. The electric potential at the centre of the circular ring is

A

`(lambda)/(epsilon_(0))`

B

`(lambda)/(2epsilon_(0))`

C

`(lambda)/(epsilon_(0))`

D

`(2lambda)/(epsilon_(0))`

Text Solution

Verified by Experts

The correct Answer is:
2
`sigma=(Q)/(A)`
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