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A closed circuit is in the form of a regular hexagon of side r. If the circuit carries current I, what is the magnetic field induction at the centre of the hexagon?

A

`(sqrt(3)mu_(0)I)/(4pia)`

B

`(sqrt(3)mu_(0)I)/(2pia)`

C

`(sqrt(3)mu_(0)I)/(3pia)`

D

`(sqrt(3)mu_(0)I)/(pia)`

Text Solution

Verified by Experts

The correct Answer is:
4

Magnetic field at `O` due to `AB, i.e`
`B=(mu_(0)I)/(4pid)(sinphi_(1)+sinphi_(2))`
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