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A straight vertical conductor carries a current. At a point `5cm` due north of it, the magnetic induction is founded to be `20muT` due east. The magnetic induction at a point `10cm` east of its will be

A

`5mu T` north

B

`10muT` north

C

`5muT` south

D

`10muT` south

Text Solution

Verified by Experts

The correct Answer is:
4

`B=(mu_(0)i)/(2pir)`
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