A proton enters a magnetic field with a ...

A proton enters a magnetic field with a velocity of `2.5 xx10^(7)ms^(-1)` making an angle `30^(@)` with the magnetic field. The force on the proton is `(B=25T)`

`1.25xx10^(-11)N`

`2.5xx10^(-11)N`

`5.0xx10^(-11)N`

`7.5xx10^(-11)N`

Text Solution

Verified by Experts

The correct Answer is:

`F=BeqV sin theta`

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