A galvanometer of resistance 20Omega is ...

A galvanometer of resistance `20Omega` is to be shunted so that only `1%` of the current passes through it. Shunt connected is `99//20Omega`

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The correct Answer is:

`S=(G)/((i)/(i_(g))-1)`

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NARAYNA-MOVING CHARGES AND MAGNETISM-LEVEL-I(C.W)

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