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The maximum potential that can be measur...

The maximum potential that can be measured with a voltmeter of resistance `1000Omega` is `6V`. Resistance that must be connected to measure a potential of `30V` with it is

A

`4000Omega` in Series

B

`6000Omega` in Series

C

`12000Omega` in Series

D

`2000 Omega` in Series

Text Solution

Verified by Experts

The correct Answer is:
1
`R=((V)/(I_(g))-G)`
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