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A charged particle moving at right angle...

A charged particle moving at right angles to a uniform magnetic field and starts moving along a circular arc of radius of curvature `'r'` . In the field it now penetrates a layer of lead and loses `3//4` of its initial kinetic energy. The radius of curvature of its path now will be

A

`4r`

B

`2r`

C

`r//4`

D

`r//2`

Text Solution

Verified by Experts

The correct Answer is:
D
`(KE_(1))/(KE_(2))=(r_(1)^(2))/(r_(2))`
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