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A horizontal wire of length 0.5m carries...

A horizontal wire of length `0.5m` carries a current of `5A`. If the mass of the wire is `10mg`, the minimum magnetic field required to support the weight of the wire is `(g=10m//g^(2))`

A

`4xx10^(-4)T`

B

`25xx10^(-4)T`

C

`4xx10^(-1)T`

D

`25xx10^(-1)T`

Text Solution

Verified by Experts

The correct Answer is:
1
`B=(mg)/(il)`
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