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A rectangular loop of wire of size 4 cm ...

A rectangular loop of wire of size `4 cm // 10cm` carries a steady current of `2A`. A straight long wire carrying `5A` current is kept near the loop `(` as shown in figu `)`. If the loop and the wire are coplanar, find the net force on the loop

A

`3.2xx10^(-5)N`

B

`1.6xx10^(-5)N`

C

`0.4xx10^(-5)N`

D

`4xx10^(-5)N`

Text Solution

Verified by Experts

The correct Answer is:
2

As `vec(F)_(AB)=-vec(F)_(DC),vec(F)_(AB)+vec(F)_(DC)=vec(0)`
`F_(AD)=k_(m)((2I_(1)I_(2))/(a))(AB)`
`=((10^(-7)N//A)(2xx5Axx2A)(10cm))/((1cm))=2xx10^(-5)N`
Similarly, `F_(BC)=0.4xx10(-5)N`
Thus, `F_(n et)=F_(AD)-F_(BC)=1.6xx10^(-5)N`
`(` towards right `)`
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