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A circular coil of 30 turns and radius 8...

A circular coil of 30 turns and radius `8.0cm` carrying a current of `6.0A` suspended vertically in a uniform horizontal magnetic field of magnitude `1.0T`. The field lines makes an angle of `60^(@)` with the normal of the coild. Calculate the magnitude of the counter torque that must be applies to prevent the coil form turning.

A

`3.13Nm`

B

`1.13Nm`

C

`2.13Nm`

D

`4.13Nm`

Text Solution

Verified by Experts

The correct Answer is:
A

The given coil is circular and is suspended such that field lines makes angle `60^(@)` with normal of the coil.
Torque on the coil, `tau=NIBA sin theta `
`tau=30xx6xx1xxpixx(8xx10^(-2))^(2)xxsin 60^(@)=3.13Nm`
A similar torque is required to prevent the coil from turning.
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(a) A circular coil of 30 turns and radius 8.0cm . Carrying a current of 6.0A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0T . The field lines make an angle of 60^@ with the normal to the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil from turning. (b) Would your answer change if the circular coil in (a) were replaced by a planar coil of some irregular shape that encloses the same area? (All other particulars are also unaltered).

(a) A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 T. The field lines make an angle of 60^@ with the normal of the coil. Calculate the magnitude counter torque that must be applied to prevent the coil from turning. (b) Whould your answer change, if the circular coil in (a) were replaced by a planer coil of some irregular shape that encloses the same area? (All other particulars are also unaltered).

Knowledge Check

  • A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0T. The field lines make an angle of 60^@ with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil from turning.

    A
    3.13 Nm
    B
    1.13 Nm
    C
    2.13 Nm
    D
    4.13Nm

  • A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30^(@) with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning is

    A
    33 Nm
    B
    3.3 Nm
    C
    `3.3 xx 10^(-2)Nm`
    D
    `3.3 xx 10^(-4)Nm`

  • A circular coil of 100turns radius 10cm, carries a current of 5A. It is suspended vertically in a uniform horizontal magnetic field of 0.5T and the field lines make an angle of 60^(@) with the plane of the coil. The magnitude of the torque that must be applied on it to prevent it from turning is

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    3.93Nm
    D
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