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A circular coil of 30 turns and radius 8...

A circular coil of 30 turns and radius `8.0cm` carrying a current of `6.0A` suspended vertically in a uniform horizontal magnetic field of magnitude `1.0T`. The field lines makes an angle of `60^(@)` with the normal of the coild. Calculate the magnitude of the counter torque that must be applies to prevent the coil form turning.

A

`3.13Nm`

B

`1.13Nm`

C

`2.13Nm`

D

`4.13Nm`

Text Solution

Verified by Experts

The correct Answer is:
A

The given coil is circular and is suspended such that field lines makes angle `60^(@)` with normal of the coil.
Torque on the coil, `tau=NIBA sin theta `
`tau=30xx6xx1xxpixx(8xx10^(-2))^(2)xxsin 60^(@)=3.13Nm`
A similar torque is required to prevent the coil from turning.
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A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0T. The field lines make an angle of 60^@ with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil from turning.

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