Two long wires carrying current `I_1` and `I_2` are arranged as shown in figure. The one carrying current `I_1` is along the x-axis. The other carrying current `I_2` is along a line parallel to the y-axis given by `x=0` and `z=d`. Find the force exerted at `O_2` because of the wire along the x-axis.

Options

A. Bil
B. `2Bil`
C. Zero
D. `sqrt(2)` Bil

Answer

3

Explanation

According to right hand thumb rule, the magnetic field due to current `I_(1)` in the wire at point `O_(2)` is along `y-` axis.
We know, magnetic force, `vec(F)_(m)=Ivec(l)xxvec(B)`
Here, `vec(B)=-Bhat(y) and hat(l)=lhat(y)`
`:. vec(F)_(m)=-IlB(hat(y)xxhat(y))=vec(0)`