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A 220-V, 50 Hz, ac generator is connecte...

A 220-V, 50 Hz, ac generator is connected to an inductor and a `50 Omega` resistance in series. The current in the circuit is `1.0 A`. What is the PD across inductor?

A

`102.2 V`

B

`186.4 V`

C

`213.6 V`

D

`302 V`

Text Solution

Verified by Experts

The correct Answer is:
3
`I = (E)/(Z), :. I = (220)/(Z), Z = 220 Omega`
`Z^(2) = R^(2) + X_(L)^(2) :. X_(L) = sqrt(Z^(2) - R^(2))`
`L = (1)/(omega) sqrt(Z^(2) - R^(2)) :. L = (1)/(2 pi f) sqrt(Z^(2) - R^(2)) = 0.68 H`
`:. V_(L) = omega L I = 2 pi xx 0.5 xx 0.68 xx 1 = 213.6 V`
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