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In a series LCR circuit R= 200(Omega) an...

In a series LCR circuit `R= 200(Omega)` and the voltage and the frequency of the main supply is 220V and 50 Hz respectively. On taking out the capacitance from the circuit the current lags behind the voltage by `30(@)`. On taking out the inductor from the circuit the current leads the voltage by `30(@)`. The power dissipated in the LCR circuit is

A

`305 W`

B

`210 W`

C

zero

D

`242 W`

Text Solution

Verified by Experts

The correct Answer is:
4
The given circuit is under resonace as `X_(L) = X_(C )`
Hence, power dissipated in the circuit is
`P = (V^(2))/(R ) = 242 W`
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