Home
Class 12
PHYSICS
An alternating current generator has an ...

An alternating current generator has an internal resistance `R_(g)` and an internal reactance `X_(g)`. It is used to supply power to a passive load consisting of a resistance `R_(g)` and a rectance `X_(L)`. For maximum power to be delivered from the generator to the load, the value of `X_(L)` is equal to

A

zero

B

`X_(g)`

C

`- X_(g)`

D

`R_(g)`

Text Solution

Verified by Experts

The correct Answer is:
3
For maximum power to be delivered from the generator to the load, the total reactance must vanish.
i.e., `X_(L) + X_(g) = 0` or `X_(L) = - X_(g)`
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    NARAYNA|Exercise LEVEL - V|83 Videos

  • ALTERNATING CURRENT

    NARAYNA|Exercise LEVEL - VI|120 Videos

  • ALTERNATING CURRENT

    NARAYNA|Exercise NCERT Based Question|1 Videos

  • ATOMIC PHYSICS

    NARAYNA|Exercise LEVEL-II (H.W)|14 Videos

Similar Questions

Explore conceptually related problems

An AC generator of 220 V having internal resistance r=10 Omega and external resistance R=100 Omega . What is the power developed in the external circuit?

A battery of internal resistance 4Omega is connected to the network of resistance as shown . In order that the maximum power can be delivered to the network, the value of R in Omega should be .

For maximum power from battery the internal resistance of battery r is

A battery is of emt E and internal resistance r . The value of external resistance R so that the power across eternal resistance is maximum :

A battery if internal resistance 4Omega is conneted to the network of resistances as shown. What must be the value of R so that maximum power is delivered to the network Find the maximum power?

A cell of emf epsilon and internal resistance r is connected across a load resistance R (i) Find the maximum power delivered at the load ? (ii) Draw the power (P ) vs load resistance ( R ) graph.

A parallel combination of two cells of emfs epsilon_(1) and epsilon_(2) , and internal resistance r_(1) and r_(2) is used to supply current to a load of resistance R. Write the expression for the current through the load in terms of epsilon_(1), epsilon_(2),r_(1) and r_(2) .

Cell A has emf 2 E ad internal resistance 4 r. Cell B has emf E and internal resistance r. The negative of A is connected to the positive of B and a load resistance of R is connected across the battery formed. If the terminal potential difference across A is zero, then R is equal to