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(x+1) is a factor of x^n+1 only if  (a)...

(x+1) is a factor of x^n+1 only if  (a)n is an odd integer   (b) n is an even integer (c )n  is a negative integer   (d)n is a positive integer

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`p(x)=(x+1) ,g(x)` where g(x) is some polynomial in `x.`
Put `x =-1`,we get,`p(−1)=(−1)^n+1=0`
If n is even , we have `p(-1)=1+1=2`
Hence `n` is odd integer , than`(x+1)` is factor of `p(x)`
So option a is correct.
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