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DeltaABC is formed by A(1,8,4),B(0,-11,4...

`DeltaABC` is formed by `A(1,8,4),B(0,-11,4)andC(2,-3,1)`. If D is the foot of the perpendicular from A to BC, then the coordinates of D are

A

`(4,5,-2)`

B

`(4,-5,2)`

C

`(-4,5,2)`

D

`(4,-5,-2)`

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The correct Answer is:
A
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