The lines (x-1)/(2)=(y+1)/(2)=(z-1)/(4) ...

The lines `(x-1)/(2)=(y+1)/(2)=(z-1)/(4) and (x-3)/(1)=(y-k)/(2)=(z)/(1)` intersect each other at point

`(-2,-4,5)`

`(-2,-4,-5)`

`(2,4,-5)`

`(2,-4,-5)`

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