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TARGET PUBLICATION-INTEGRATION-CRITICAL THINKING
- Evaluate: (i) intsin^(-1)(cosx)\ dx ,\ \ 0lt=xlt=pi (ii) inttan^(-1){...
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- If int(cosx-sinx)dx=sqrt(2)sin(x+alpha)+c, " then " alpha=
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- intsin3xcos4x dx=
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- int(1)/(tanx+cotx)dx=
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- int2sinxcosxdx is equal to
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- intsqrt(1+sin2x)dx is equal to
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- int(sinx+cosx)/(sqrt(1+sinx))dx
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- 4int(sin^(3)x+cos^(3)x)/(sin^(2)2x)dx=
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- int1/(cos2x+sin^2x) dx
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- int(cos2x-cos2alpha)/(cosx-cosalpha)dx
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- intsqrt(2+sqrt(2+sqrt(2+2cos8x)))dx=
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- int(sin^(4)x-cos^(4)x)dx=
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- (sin^(8)x-cos^(8)x)/(1-2sin^(2)xcos^(2)x)
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- int tan^(-1)( sqrt((1-cos2x)/(1+cos2x)))dx
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- inttan^(-1)(sinx/(1+cosx))dx=
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- "If " int(cos 4x+1)/(cotx-tanx)dx=Acos4x+B, " then "
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- intcos.(x)/(16)cos.(x)/(8)cos.(x)/(4)cos.(x)/(2)sin.(x)/(16)dx=
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- Evaluate : int(sin^6x+cos^6x)/(sin^2xdotcos^2x)dx
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- int(cotxtanx)/(sec^(2)x-1)dx=
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- int(1+cos^(2)x)/(sin^(2)x)dx=
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